haroldstork@lemm.ee to Lemmy Shitpost@lemmy.worldEnglish · 18 days agomathpostingfiles.catbox.moeimagemessage-square9fedilinkarrow-up153arrow-down10
arrow-up153arrow-down1imagemathpostingfiles.catbox.moeharoldstork@lemm.ee to Lemmy Shitpost@lemmy.worldEnglish · 18 days agomessage-square9fedilink
minus-squareCreatingMachines@fedia.iolinkfedilinkarrow-up5·18 days agoLeaving a comment to remember to check this post again, in case someone drops the answer to this.
minus-squareMBM@lemmings.worldlinkfedilinkarrow-up4·edit-218 days agoUnless you know algebraic topology it’s kind of hopeless (but that’s the joke). If you’re curious, it’s the first example on the page on cohomology rings. Edit: So, you could say H●(🌭;🍔) = 🍔[🥚] / (🥚n+1) where |🥚| = 1.
minus-squareLeate_Wonceslace@lemmy.dbzer0.comlinkfedilinkEnglisharrow-up1·edit-218 days agoNo, it’s the integers Mod 2 (Notation “Z/2Z” where Z is the Integers) which is the only group of order 2 and the smallest non-trivial field.
Leaving a comment to remember to check this post again, in case someone drops the answer to this.
Unless you know algebraic topology it’s kind of hopeless (but that’s the joke). If you’re curious, it’s the first example on the page on cohomology rings.
Edit: So, you could say H●(🌭;🍔) = 🍔[🥚] / (🥚n+1) where |🥚| = 1.
🍪 = 2
🍔 = 1/2
No, it’s the integers Mod 2 (Notation “Z/2Z” where Z is the Integers) which is the only group of order 2 and the smallest non-trivial field.